C_6H_5-CO-CHO xrightarrow{conc. OH^-} (A) xri | vedclass

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(A) $1$. The reaction of phenylglyoxal $(C_6H_5-CO-CHO)$ with concentrated $OH^-$ undergoes an intramolecular Cannizzaro reaction to form the mandelat

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Benzene

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(A) $1$. The reaction of phenylglyoxal $(C_6H_5-CO-CHO)$ with concentrated $OH^-$ undergoes an intramolecular Cannizzaro reaction to form the mandelate ion $(A)$,which is $C_6H_5-CH(OH)-COO^-$.$2$. Acidification with $H_3O^+$ yields mandelic acid $(B)$,which is $C_6H_5-CH(OH)-COOH$.$3$. Oxidation with $KMnO_4$ cleaves the side chain to form benzoic acid $(C_6H_5-COOH)$.$4$. Decarboxylation of benzoic acid with soda lime $(NaOH/CaO/\Delta)$ yields benzene $(C_6H_6)$.

$C_6H_5-CO-CHO$ $\xrightarrow{conc. OH^-} (A)$ $\xrightarrow{H_3O^+} (B)$ $\xrightarrow[2. NaOH/CaO/\Delta]{1. KMnO_4} (C)$
Product $(C)$ is:

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$C_6H_5-CO-CHO$ $\xrightarrow{conc. OH^-} (A)$ $\xrightarrow{H_3O^+} (B)$ $\xrightarrow[2. NaOH/CaO/\Delta]{1. KMnO_4} (C)$Product $(C)$ is: